assalamualaikum mohon bantuannya teman semua
Jawab:
Penjelasan dibawah
Penjelasan dengan langkah-langkah:
Soal a
[tex]\begin{aligned} \lim_{x \to c} \left[ \frac{f(x)}{2g(x)} \right] + h(x) &= \frac{ \lim_{x \to c} f(x)}{ \lim_{x \to c} [2g(x)]}+h(x) \\ &= \frac{f(c)}{2 \lim_{x \to c} g(x)} +h(x) \\ &= \frac{f(c)}{2g(c)} + h(x)\end{aligned}[/tex]
Soal b
[tex]\begin{aligned} \lim_{x \to 1} \frac{k(3x+3)}{k} &= \frac{ \lim_{x \to 1} k(3x+3)}{ \lim_{x \to 1} k}\\&= \frac{ \lim_{x \to 1} (3kx+3k)}{k} \\ &= \frac{3k (\lim_{x \to 1} x) + 3k}{k} \\ &= \frac{3k (1) + 3k}{k} \\ &= \frac{k(3+3)}{k} \\&=3+3 \\ &= 6\end{aligned}[/tex]
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